Решение задачи
- \( y^′=12-12\sqrt{2}\cos x=0\\\cos x=\frac{\sqrt{2}}{2}\\x=\frac{\pi}{4}\ из\ \left( 0;\frac{\pi}{2}\right) \)
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\[ y(0)=3-30+0+0=3-3\pi\\y(\frac{\pi}{4})=3-3\pi+3\pi-12\sqrt{2}\frac{\sqrt{2}}{2}=3-12=-9\\y(\frac{\pi}{2})=3-3\pi+6\pi-12\sqrt{2} \]